2x^2+2.6x-1.69=0

Solution for 2x^2+2.6x-1.69=0 equation:

2x^2+2.6x-1.69=0

a = 2; b = 2.6; c = -1.69;
Δ = b2-4ac
Δ = 2.62-4·2·(-1.69)
Δ = 20.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.6)-\sqrt{20.28}}{2*2}=\frac{-2.6-\sqrt{20.28}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.6)+\sqrt{20.28}}{2*2}=\frac{-2.6+\sqrt{20.28}}{4}
$